Question

In the figure, ABCD is a triangle and O is a point in it. OP and OQ are drawn perpendicular to the sides AB and BC respectively. If angle B = 65 degree, Find angle POQ.​

Answer 1

Step-by-step explanation:

Given:anglePBQ=60degrees

RTF:anglePOQ

Ans:angleBPO+angleBQO+anglePBQ+anglePOQ=360degrees (Angle sum property)

90+90+60+anglePOQ=360

240+anglePOQ=360

anglePOQ=360-240

anglePOQ=120degrees

Answer 2

Step-by-step explanation:

AngleBPO+BQO+PBQ+POQ=360 degree(ASP)

90degree+90degree+65degree+POQ=360 degree.

245degree+POQ=360 degree

POQ=360-245=115 degree....

Hope it helps...