Question

In the figure ABCD is trapezium. Diagonals AC and BD intresect at m. Area of triangle ABC is 24 cm square and area of triangle AMD is 10 cm square

1-find the area of triangle BMC
2-how much is area of triangle AMD? Write the reason

Answer 1

answer

14cm

since all triangle with the same base

and the 3rd vertex on a line parallel to

the base have the same area,

triangle ACB = triangle ADB

triangle AMB =10cm (common to both

triangle ACB and ADB)

so, ACB-AMB =14cm

ADB-AMB =14cm