Question

in the figure, ABCDEF is a regular hexagon, prove that ACDF is a rectangle

Answer 1

where is fig dear???

Answer 2

ACDF is a rectangle if in the figure, ABCDEF is a regular hexagon

Step-by-step explanation:

AB + BC = CD = DE = EF = AF

∠A = ∠B = ∠C =∠D = ∠E = ∠F = 120°

in ΔABC

AB = BC & ∠B = 120°

=> ∠BAC =∠BCA = 30°

=>∠A in ACDF = 120° - 30° = 90°

∠C in ACDF = 120° - 30° = 90°

Similarly we can show other angles

∠D = ∠F = 90°

Hence ACDF is a rectangle

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