In the figure, ABCE and ABDE are cyclic quadrilaterals. Given that <EAB=100⁰, <EPD=75°. Find
a) <EDB
b) <DEP
c) <ECB
d) <CBD
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Given, ∠EAB=120
o
,∠EPD=100
o
,∠EDB=60
o
(ABCD is a cyclic quadrilteral, opposite angles are supplementary, 180−120=60
o
)
∠ECB=60
o
- (Same arc angle equal)
In ABPC,∠C=60,∠P=100
o
∠B=180−(100+60)=20
o
ie., ∠DBC=20
o
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