Question

In the figure, ∠ABD = 3 ∠DAB and ∠BDC = 96 degrees . Find ∠ABD

Answer 1

let ∠a be x
let ∠b be 3x
so ,
the equation formed is :
x+3x+96=180(angle sum property of triangle)
4x=180-96
4x=84
x=84÷4
x=21=∠DAB
∴ ∠abd= 21*3=63

Answer 2

<ABD=3<DAB

<BDC =96 degree

<ABD = ?

<ABD + <BDC = 180 degree

<ABD + 96 degree = 180 degree

<ABD = 180-96 degree

<ABD = 84 degree

In <BAD

<D = 84 degree

<A =X

<B =3x

84+x+3x = 180

84+4x =180

4x=180-84

4x =96

x=96 divided 4

x = 24

<B =3x

<B = 3*24

<B =72