Question

in the figure, ∠ABD = 3 ∠DAB and ∠BDC = 96 degrees
. Find ∠ABD

in the triangle ABC.
AC is base and top vertex is B. There is a line segment BD from vertex B to D ( on the line segment AC)

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

<ABD = 72°

Step-by-step explanation:

Given:

In ∆ABC ,

<ABD = 3<DAB

<BDC = 96°

To Find:

<ABD = ?

proof:

Let <DAB = x°

<ABD = 3x°,

In ∆ABD , AD extended to C .

Sum of interior opposite angles = exterior angle at D .

=> <ABD + <DAB = <BDC

=> 3x° + x° = 96°

=> 4x° = 96°

/* Divide both sides by 4, we get

=> x° = 24

Therefore,

<ABD = 3x = 3×24 = 72°

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