Question

in the figure, about divides angle DAC in the ratio 3:2 ,find angle ACB and ABC​

Answer 1

Answer: ∠ABC  = 100°

            ∠ACB = 60°

Explanation:

In the figure, ∠DAX = 180° ( Linear pair)

⇒∠CAX + ∠CAD = 180°

⇒130° + ∠CAD = 180°

⇒∠CAD= 180°- 130°= 50°

Let ∠DAB and ∠BAC be 3x and 2x respectively.

∠CAD= 50°

⇒∠DAB + ∠BAC = 50°

⇒3x + 2x = 50°

⇒5x = 50°

⇒x = 10°

∴∠DAB = 3x = 30°  and ∠BAC = 2x = 20°

In ΔABD, ∠DAB +∠ADB +∠ABD = 180°( Angle Sum Property)

               ⇒30° + 70° + ∠ABD= 180°

              ⇒∠ABD=  180° - 100°= 80°

Now , ∠ABD + ∠ABC = 180°

   ⇒  80° + ∠ABC = 180°

   ⇒  ∠ABC = 180° - 80°

   ⇒  ∠ABC  = 100°

In ΔABC,  ∠ABC +∠ACB +∠BAC = 180°( Angle Sum Property)

      ⇒ 100° + ∠ACB + 20° = 180°

      ⇒ ∠ACB = 180° - 120°

     ⇒ ∠ACB = 60°

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Answer 2

Answer:

hi

first of all I want know your intro and class

birthday- 10 April

biggest fear - when I lies for a big meal

First kiss - many has been proposed me but I've not accept so it means I don't have given to anyone but when i impressed to some so I will see

Sports u play - badminton

Future carrier - ya I want to do great jee

can u give your intro