In the figure above, BC || PQ. BP and CQ intersect at O. If x + y = 80° and :- y=55°, then find .x and y
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X= 25 , Y= 55 , Z= 100
Step-by-step explanation:
given, X + Y = 80°
X + 55° = 80°
X = 80° - 55°
X = 25°
Now, angle OCB = angle Y (by alternate interior angles)
angle OCB = 55°
Now , angle BOC = angle QOP (vertically opposite angles)
angle BOC = angle Z
in a triangle, sum of all angle is 180°
therefore,
angle BOC + angle OBC + angle OCB = 180°
Z + 25° + 55° = 180°
Z + 80° = 180°
Z = 180° - 80°
Z = 100°
all angles of triangle are 100° , 55° , 25°
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