In the figure above, O is the centre of the circle such that OM perpendicular AB . If angle ABC =42 degree, find angle AOC and angle DOC. Prove that AOCD is a cyclic quadrilateral. Tell this I will mark you as brainliest
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Answer:
use the tangent formula..........
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Step-by-step explanation:
ANSWER
∠ADC=
2
1
∠AOC
(Angle subtended by a chord on mayor area is half of that subtended on center)
∴∠ADC=
2
1
×130=65
∘
Now, ADCB is cyclic quadrilateral ⇒
Sum of opposite Angles is 180
∘
∴∠ABC+∠ADC=180
∘
∠ABC+65=180
∘
∠ABC=115
∘
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