Question

in the figure above, pq is the perpendicular bisector of line ab. If angle xab=40° and angle xby=10°, then find angle ayx​

Answer 1

GiveN :-

• ∠XAB = 40°
• ∠XBY = 10°
• ∠AMY = 90°

To FinD :-

• Value of ∠AYX

SolutioN :-

∠YAX = ∠XBY

∠YAX = 10°

∠YAB = ∠XAB + ∠YAX

∠YAB = 40° + 10°

∠YAB = 50°

In ∆ APM

→ ∠YAB + ∠AMY + ∠AYX = 180°

→ 50° + 90° + ∠AYX = 180°

→ 140° + ∠AYX = 180°

→ ∠AYX = 180° - 140°

→ ∠AYX = 40°

Answer 2

Answer:

130°.

Step-by-step explanation:

The angle XAY = 40°

The and ybx=10°

The angle AMY = 90° as the line PQ I'd perpendicular on AB.

SO AXM =180-(40°+90°)

=180°-130°=50°

so angle AXM = 40°

From the property that the sum of adjacent angle of is equal to outer angle so we can find it

angle AXY[=Angle AMX+angle MAX

=90°+40°= 130"

The angle AXY is 130°....