In the figure Ac= 17 cm, AB = 15
Find (1) BC (i) AD
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Answer:
a) Given AD ⊥ BC, AB = 25 cm, AC = 17 cm and AD = 15 cm.
Δ ADC is a right triangle.
∴AC2=AD2+DC2 [Pythagoras theorem]
∴172=152+DC2
289=225 + DC2
∴DC2 = 289−225
∴DC2 = 64
Taking square root on both sides,
DC=8cm
ΔADB is a right triangle.
∴AB2=AD2+BD2 [Pythagoras theorem
252 = 152 + BD2
625=225 + BD2
∴BD2=625−225=400
Taking square root on the both sides.
BD=20cm
∴BC=BD+DC
= 20+8
= 28cm
Hence the length of BC is 28cm.
Step-by-step explanation:
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