In the figure, AC= 24cm and BC= 10cm and o is the centre of the circle . Find the area of the shaded region.
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in ∆ABC
by Pythagoras theorem
AB^2= BC^2 + CA^2
AB= √576+100
AB=26
area of Semicircle - area of triangle
1/2πr^2-1/2 base × height
1/2π(13^2- 1/2 ×24×10
1/2×22/7(169-120)
11/7(49)
77cm^2=area of shadeed portion
Pratishtha2003:
its wrong dude
u cannot take pi as common
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