Question

in the figure AC = 24cm BC=10 cm and O is the centre of the civkr . Find the area of the shaded region.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

area of triangle=1/2*24*10

= 120cm²

AB²=AC²+BC²

AB =26

R of circle = 26/2 =13cm

area of circle=22/7*13*13

area of half circle =(22/7*13*13)/2

now, area of shaded part=area of circle - (area of half circle + area of triangle)