Question

In the figure, AC=AD=20 in, BC=9 in, CD=15 in, and BD is perpendicular to AC. What is the number of square inches in the positive difference between the areas of ACD and BEC? Express your answer as a decimal to the nearest tenth.

Answer 1

Step-by-step explanation:

BAC=∠CAD=20

o

∠BCD=140

o

(180−40=140 cyclic quadrilateral)

∠ADC=90

o

(angle of the semicircle)

∠CDM=∠BAC=20

o

(angle in the same arc).

∠BAP=140

o

.(180−40=140,linearpair)