In the figure, AC=AD=20 in, BC=9 in, CD=15 in, and BD is perpendicular to AC. What is the number of square inches in the positive difference between the areas of ACD and BEC? Express your answer as a decimal to the nearest tenth.
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Anonymous:
which class question?
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Step-by-step explanation:
BAC=∠CAD=20
o
∠BCD=140
o
(180−40=140 cyclic quadrilateral)
∠ADC=90
o
(angle of the semicircle)
∠CDM=∠BAC=20
o
(angle in the same arc).
∠BAP=140
o
.(180−40=140,linearpair)
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