Question

In the figure AC = BC, angle DCA =angle ECB and angle DBC= angle EAC. Prove that DC = EC. where is this question from????

Answer 1

This question is from congruency

In ∆ACE and ∆DCB

AC = BC

angle ECB =angle DCA

angle EAC = angle DBC

∆ACE =~= ∆BCD (by AAS)

Dc = EC (by cpct)