Question

in the figure AC is equal to 24 cm BC is equal to 10 cm and O is the centre of the circle find the area of shaded region.

Answer 1

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Answer 2

Answer:

$\Rightarrow Area=145.57cm^2$ is the area of shaded region.

Step-by-step explanation:

We have been given  a figure  we need to find the shaded region:

$AB^2=AC^2+BC^2$

AC=24 and BC=10

$AB^2=24^2+10^2$

$AB^2=676$

$AB=26$

AB is the diameter and

$Radius=\frac{Diameter}{2}$

$Radius=\frac{26}{2}=13$

Area of shaded region=Area of semicircle- area of triangle ACB

$Area=\frac{\pi\cdot r^2}{2}-\frac{1}{2}\cdot\text{base}\cdot\text{height}$

$Area=\frac{\frac{22}{7}\cdot 13^2}{2}-\frac{1}{2}\cdot 10\cdot 24$

$Area=265.57-120$

$\Rightarrow Area=145.57cm^2$ is the area of shaded region.