In the figure AC Is the bisector of both
.
<A and <C also <B = 90°
a)<b
b) If AB = 4cm
CD = 3cm
Find Apand AC
A
B
'D
3
С
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Answer:
In △ABC,
⇒ AB=AC [ Given ]
⇒ ∠ABC=∠ACB [ Base angles of equal sides are also equal. ]
⇒ ∠ABC=75o
∴ ∠ACB=75o
⇒ ∠ABC+∠ACB+∠BAC=180o
⇒ 75o+75o+x=180o
⇒ 150o+x=180o
⇒ x=30o.
It is given that, AC bisects ∠A
∴ ∠BAC=∠CAD
∴ ∠CAD=30o
In △ACD,
⇒ AD=CD [ Given ]
⇒ ∠CAD=∠ACD [ Base angles of equal sides are also equal. ]
∴ ∠ACD=30o
⇒ ∠CAD+∠ACD+∠CDA=180o
⇒ 30o+30o+y=180o
⇒ 60o+y=180o
⇒
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