In the figure AD = 1/2AB, AE = 1/2AC, if AB = AC. Show that BD = CE.
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If D is the midpoint of BC and ED produced to meet AB at F and CP and DQ ... The side AC of triangle ABC is produced to E such that CE=1/2 AC. ... Prove that FD=I/3 FE.
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2
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AB=AC. -eq1
Then,
AD = AE. -eq2
AB = AD + BD. -eq3
AC = AE + CE. -eq4
From EQ 1
AD + BD = AE + CE
BD = CE. ( from EQ 2 AD= AE)
Hence, proved
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