Question

In the figure AD=AE and BD=CE. prove that DE||BC.​

Answer 1

Step-by-step explanation:

We have AE=AD and CE=BD.

Adding, we get AE+CE=AD+BD

⇒AC=AB.

In triangles AEB and ADC, we have

AE=AD .. (given);

AB=AC .. (proved);

∠EAB=∠DAC, (common angle).

By SAS postulate △AEB=△ADC..