Question

In the figure AD = BC = 5 cm. What is the length of CF if B is the mid point of ED And DF ​

Answer 1

Step-by-step explanation:

Given: D and E are mid points of BC and AB respectively. DF∥CE

In △BEC,

FD∥CE and D is mid point of BC

Hence, by converse of mid point theorem, F is mid point of BE.

Hence, FB=

2

1

(BE)

FB=

2

1

(

2

1

AB) (E is mid point of AB)

FB=

4

1

AB