Question

In the figure, AD = BC, AngleADC = angleBCD =90°. PROVE THAT TRIANGLE ADC IS EQUAL TO BCD.​

Answer 1

Answer:

by using similarlity chapter we prove

Answer 2

Answer:

to prove triangle equal ,what we are gonna do is (A-S-S) TEST i.e angle - side - side

they have angl ACD = angl BDC ----( BOTH ARE 90°)

SIDE CD is common in both the angle

side AD=BC ---(GIVEN)

therefore both triangle are equal