Question

In the figure AD bisects angleA and AD perpendicular to BC. a)Is triangle ADB conqruent to triangle ADC? Why? b) Is BD equals DC? Why?

Answer 1

Answer:

in ΔABD and ΔADC,

angle BAD = Angle DAC=1/2 of angle A

AD=AD

ANGLE ADB = ANGLE ADC

HENCE, triangle ABD is congruent to triangle ADC(BY ASA)

BD=DC(c.p.c.t)

Answer 2

Answer:

in ΔABD and ΔADC,

angle BAD = Angle DAC=1/2 of angle A

AD=AD

ANGLE ADB = ANGLE ADC

HENCE, triangle ABD is congruent to triangle ADC(BY ASA)

BD=DC(c.p.c.t)

Step-by-step explanation: