Question

In the figure AD is a median ot a triangle ABC and AM1 BC then AD? - BC DM + (89)
B.
b
Q AB
O AC2
OBO2

urgently needed answer​

Answer 1

Answer:

Step-by-step explanation:

If in triangle ABC, AD is a median and AM is perpendicular to BC, then prove that AB2 = AD2-BC*DM + 1/4 BC2. 1. See answer. Add answer ... D is the midpoint of BC and AM ⊥ BC. In right angled triangle ABM, ... DM + BC²/4. Hence proved. tramwayniceix and 418 more users found this answer helpful

Answer 2

Step-by-step explanation:

the answer is above given thank for free point bro