Question

in the figure ,AD is median of triangle ABC .prove that ar (TRIANGLEABD)=ar (TRIANGLEACD)​

Answer 1

Step-by-step explanation:

In ABD and ACD

• AB = AB ( common )
• Angle ADB = Angle ACD ( each 90 )
• BD = CD ( median of the traingle )

By S A S

ABD congruent ACD

Triangle ABD = Triangle ACD

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Answer 2

ar (ABD) = ar (ADC)

Step-by-step explanation:

given that : ABC is a triangle and AD is the median

to prove : ar (ABD) = ar (ADC)

construction : draw AL ⊥ BC

prrof :

since , AD is the median of triangle ABC , therefore , D is the mid point of BC

BD = DC

multiply both sides by AL

BD × AL =DC ×AL

$\frac{1}{2} (BD \times AL) = \frac{1}{2} (DC \times AL)$

$ar (\bigtriangleup ABD ) = ar (\bigtriangleup ACD )$

hence , proved

#Learn more:

In the given figure, AD is the median of triangle ABC and E is the midpoint of AD. prove that ar(triangle BDE)=ar(triangle ABC)

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