Question

In the figure AD is the altitude of A  ABC and AB = AC. If 3BD = 3AD and 3DE = 4AD. Prove that BEsquare=AEsquare+AB SQUARE

Answer 1

Answer: Step-by-step explanation:

Given that,

△ABC is an isosceles triangle

so,

AB=AC−−(i)

Also, AD is the altitude

so, ∠ADC=∠ADB=90−−−(ii)

To prove :

(i)BD=CD

(ii)∠BAD=∠CAD

Proof :-

In △ADB and △ADC

∠ADC=∠ADB=90

AB=AC[from (i)]

AD=AD

△ADB≅△ADC

Hence,by CPCT

BD=DC

and

∠ABC=∠DAC

hence,proved

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