Question

In the figure, AD is the ________ and _______ of the triangle ABC​

Answer 1

Answer:

i hope it helps

Step-by-step explanation:

Let ar(△ABD)=x

since D is mid point of BC.

ar(△ADC)=x.

Given,

ar(△ADP)=

3

2

ar(△ABD)

⇒ar(△ADP)=

3

2

x.

ar(△DPC)=ar(△ADC)−ar(△ADP)

=x−

3

2x

=

3

x

i) AP:PC=ar(△ADP):ar(△PDC) [since both triangles have height]

=

3

2x

:

3

x

=2:1

ii) ar(△PDC):ar(△ABC)=

3

x

:2x

=1:6

solution