In the figure AD perpendicular BC. D is the midpoint of BC
Using SAS Congruence rule show that
triangle ABD congruent to triangle ACD
Is AB = AC? Why?
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In ∆ ADB & ∆ ADC
- BD = DC......given
- angle ADB = angle ADC = 90°.....common angle
- AD = AD......common side
- therefore,
- ∆ ADB is congruent to ∆ ADC by side angle side test of congruence
- AB = AC........congruent parts of congruent triangles....from 5
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