In the figure AE bisect angle BAD and AF bisect angle CAD show that angle EAF=90
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∠EAF = 90°
Step-by-step explanation:
Given, that AE bisects the angle BAD,
Let angle BAD = x
therefore angle BAE = x/2 and angle EAD = x/2
Given, that AF bisect angle CAD,
Let angle CAD = y
therefore angle CAF = y/2 and angle DAF = y/2
we know that sum of the angles on a linear pair is equal to 180,
therefore ∠BAD + ∠CAD = 180°
∠BAD/2 + ∠CAD/2 = 180/2
x/2 + y/2 = 90°
∠EAD + ∠DAF = 90 (From above)
∠EAF = 90° (from figure)
Hence proved.
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