Question

in the figure AE bisects angle DAC and angle B =angle C prove that AE is parallel to BC​

Answer 1

Answer:

DAC =B +C (EXTERIOR ANGLE = SUM OF INTERIOR OPPOSITE ANGLES)

DAC = 2C AS (B =C) GIVEN

1/2DAC =C (DEVIDING BY 2)

EAC = C (1/2DAC =EAC) GIVEN

HENCE AE IS PARALLEL TO BC AS ALTERNATE INTERIOR ANGLES ARE EQUAL