Question

In the figure alongside ABCD is a rhombus. if angle ADB = 40 find the size of angle CDE

Answer 1

Answer:

140°

Step-by-step explanation:

CDB=40°

AB=AD.

so,ABD=40°

BAD=100°.(angle sum property.)

In a rhombus,opposite angles are equal.

C=100°

BC=CD

so,CBD=CDB=40°

CDE is exterior angle to ∆BCD.

so,CDE=140°

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