In the figure an equilateral triangle, a square, a regular hexagon are put together
a) what is the measure of the inner angles of a polygon
b) find angle ABC
Answers
Given : in figure an equilateral triangle, a square, a regular hexagon are put together
To Find : a) what is the measure of inner angles of each polygon?
B) find ∠ABC
Value of S
Solution:
Inner angle of a Regular polygon = (n-2)180° / n
Inner angle of equilateral triangle = (3 - 2) 180° / 3 = 60°
Inner angle of Square = (4 - 2) 180° / 4 = 90°
Inner angle of regular Hexagon = (6 - 2) 180° / 6 = 120°
∠ABC = Angle of Square + angle of Equilateral triangle
= 90° + 60°
= 150°
∠S = 360° - ( Angle of Square + angle of Equilateral triangle + angle of regular Hexagon )
=> ∠S = 360° - ( 90° + 60° + 120° )
=> ∠S = 360° - ( 270° )
=> ∠S = 90°
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