Question

In the figure angle ABC = 69° and angle ACB= 31° find the angle BDC

Answer 1

In ∆ABC. ∠BAC + ∠ABC + ∠ACB = 180 degree

[Sum of all the angles of a triangle is 180 degree ]  

 ⇒ ∠BAC + 69 degree + 31 degree = 180 degree

 ⇒ ∠BAC + 100 degree = 180 degree

 ⇒ ∠BAC = 180 degree - 100 degree = 80 degree  

 Now, ∠BDC = BAC = 80 degree .

hopeits help you

thanx and be brainly.............................

Answer 2

Hello mate =_=

____________________________

Solution:

∠ABC+∠ACB+∠BAC=180°

⇒69°+31°+∠BAC=180°

⇒∠BAC=180°−69°−31°=80°       ........(1)

∠BAC=∠BDC  (Angles in the same segment are equal)      .......(2)

From (1) and (2), we can say that

∠BDC=80°

hope, this will help you.

Thank you______❤

_____________________________❤