Question

in the figure angle ABC and angle CDE are equilateral triangles. prove that : AD = BE.​

Answer 1

Answer:

no I think I you can do better

Answer 2

Answer:

∠ADC=∠BCD=90

∘

→square

∠CDE=∠DCE=60

∘

→equilateral_triangle

∴∠ADE=∠BCE=150

∘

InΔADEandΔBCE

AD=BC

DE=CE

∠ADE=∠BCE

ΔADE≅ΔBCE