Question

in the figure angle ABC is equal to 90 degree and AB is equal to BC find AB and BC hence ab equals to BC hence angle BAC is equals to angle BCA?​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation

In △ABD and △ABC we have  BD=BC

AB=AB [Common]    

∠ABD=∠ABC=90  

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∴ By SAS criterion of congruence we get    

△ABD≅△ABC  

⇒AD=AC and ∠DAB=∠CAB [By CPCT]  

⇒AD=AC and ∠DAB=x [∴∠CAB=x]    

Now, ∠DAC=∠DAB+∠CAB=x+x=2x

∴∠DAC=∠ACD

⇒DC=AD [Side Opposite to equal angles]

⇒2BC=AD since DC=2BC

⇒2BC=AC Since AD=AC

Hence proved.