Question

in the figure angle ACD is an exterior angle of the triangle abc angle b is 30 degree angle a is 70 degree find the measure of angle ACD​

Answer 1

Answer:

We are given m∠B=40

o

m∠A=70

o

Now,

BD

is a straight ray

so, m∠ACB+m∠ACD=180

o

→(1)

In △ABC,m∠A+m∠B+m∠ACB=180

o

→(2)

From (1) & (2)

m∠A+m∠B=m∠ACD

so, m∠ACD=40

o

+70

o

m∠ACD=110

o

pls Mark me as brainlist

Answer 2

Answer:

100 is the correct answer