Question

In the figure angle ACR=120°and CBQ=140°then find all angles of triangle ABC

Answer 1

Answer:

Step-by-step explanation:

figure is a CR = 120 degree and angle cb2 = 140 degree find all the angles of angle abc

Answer 2

Angles of the ΔABC are as follows; ∠BAC = 80° ∠BCA = 40°

GIVEN

∠ACR = 120°

∠CBQ = 140°

TO FIND

The angles of the triangle ABC

SOLUTION

We can simply solve the above problem as follows;

It is given,

∠ACR = 120°

∠CBQ = 140°

We know that,

∠ACR + ∠ACB = 180° (Angles of straight line)

120° + ∠ACB = 180

∠ACB = 180-120 = 60°

Similarly,

∠CBQ + ∠BCA = 180°

140 + ∠BCA = 180

∠BCA = 180-140 = 40°

In ΔABC

We know,

∠ABC + ∠ACB + ∠BAC = 180° (Sum of interior angle of a triangle)

Putting the values of ∠ACB and ∠ABC

40 + 60 + ∠BAC = 180

100 + ∠BAC = 180

∠BAC = 180-100

∠BAC = 80°

Hence, Angles of the ΔABC are as follows; ∠BAC = 80° ∠BCA = 40°∠ABC = 60°

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