Question

in the figure, angle aob, is a staright line, if angle aoc = 40 degree , angle cod=4x degree and angle BOD =3x degree then angle cod=​

Answer 1

Answer:

angle cod =80 degree

Step-by-step explanation:

as angle aob is a straight line.

so angle aoc + angle cod + angle bod = 180

=> 40+ 4x+ 3x= 180

=> 40 + 7x= 180

=> 7x= 180- 40

=> x = 140/7

=> x = 20

so angle cod = 4(20)

angle cod = 80degree

Answer 2

The Schematic of the angles is given in the figure

Given:

∠AOC = 40°

∠COD = 4X°

∠BOD = 3X°

and,

∠AOB is a straight line.

This implies that ∠AOB is 180°.

we know that a straight line makes an angle of 180 degrees. It means that the sum of all the angles will be 180 degrees.

Hence, we can write:

∠AOC  + ∠COD  + ∠BOD = 180°

=> 40° + 4X° + 3X° = 180°,

Rearranging the equation:

=> 4X° + 3X° =  180° - 40°

=> 7X° = 140°

=> X° = 140°/7

=> X° = 20°

As it is known ∠COD = 4X°,

putting the value of X = 20° in above equation,

∠COD = 4 X 20°

= 80°

Hence, ∠COD = 80°

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