in the figure, angle B < angle A and angle C < angle D show that AD <BC
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∠A>∠B
⇒BO>AO (SIDE OPP TO LARGER ANGLE IS LONGER) (1)
∠D>∠C
⇒OC>OD(" " " " ") (2)
adding 1 and 2, we get
BO+OC>AO+OD
⇒BC>AD
HENCE PROVED
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