Question

in the figure angle BAC is equal to 90 degree and AD perpendicular to BC then prove that BD X CD is equal to AD square​

Answer 1

Answer:

i hope this will help u to get your solution . all the best

Answer 2

Answer:

$AD^{2}$ = $BD\times CD$

Step-by-step explanation:

In this question

We have given that

∠BAC = 90°

AD ⊥ BC

So , prove that $AD^{2}$ = $BD\times CD$

Prove ⇒  In ΔABD and ΔCAD

$L_1$ = $L_2$ (AD bisect CA)

AD is common

$L_3$ = $L_4$ = 90°

So ΔABD ≅ ΔCAD

Therefore, $\frac{BD}{AD}$ = $\frac{AD}{CD}$

$BD\times CD$ = $AD^{2}$

Hence, $AD^{2}$ = $BD\times CD$