Question

In the figure angle bac is equal to 90 degree and ad perpendicular to bc then prove that bd x cd is equal to ad square​

Answer 1

Step-by-step explanation:

In this question

We have given that

∠BAC = 90°

AD ⊥ BC

So , prove that AD^{2}AD

2

= BD\times CDBD×CD

Prove ⇒ In ΔABD and ΔCAD

L_1L

1

= L_2L

2

(AD bisect CA)

AD is common

L_3L

3

= L_4L

4

= 90°

So ΔABD ≅ ΔCAD

Therefore, \frac{BD}{AD}

AD

BD

= \frac{AD}{CD}

CD

AD

BD\times CDBD×CD = AD^{2}AD

2

Hence, AD^{2}AD

2

= BD\times CDBD×CD