Question

In the figure angle BAD=3 angle DBA,find angle CDB,angle DBC and angle ABC​

Answer 1

Answer:

In△ABD

3θ+θ+104=180

=>4θ=76

∘

=>θ=19

∘

104

∘

+∠BDC=180

∘

(sum of angles on a straight line=180

∘

)

=>∠BDC=76

∘

In△BDC:

=>76

∘

+65

∘

+∠DBC=180

∘

=>∠DBC=39

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∠ABC=∠ABD+∠DBC

=θ+39

∘

=19

∘

+39

∘

=58

∘