in the figure angle BAD=40 then find angle BCD
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sides AO=BO=CO=DO................radius of same circle
angles AOB=COD.............. opposite angles
triangles AOB=COD............SAS test
hence angle BAD=BCD
BAD=40
hence, BCD=40
angles AOB=COD.............. opposite angles
triangles AOB=COD............SAS test
hence angle BAD=BCD
BAD=40
hence, BCD=40
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Answer:
Step-by-step explanation:
We know that,
Triangles on same base have equal corresponding angles.
Here,
TriangleBAD and TriangleBCD are on same(imaginary)base BD.
Therefore, AngleBAD=AngleBCD=40
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