Math, asked by nellore, 1 year ago

In the figure Angle BAD=a degrees and angle ABC=c degrees and angle BCD=b degrees then angle ADC is

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Answered by rajeev378
30
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Here is your answer in the attachment


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Answered by MonarkSingh
30
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In the figure
Angle C(major arc) = 360° - b°
(as Complete angle is 360°)

So In Quadrilateral ABCD

/_ A + /_B + /_C + /_D = 360°

a° + b° + 360° - b° + /_D = 360°

/_D = b° - c° - a°

Therefore
Angle ADC IS = b° - a° - c°

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