In the figure Angle BAD=a degrees and angle ABC=c degrees and angle BCD=b degrees then angle ADC is
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Here is your answer in the attachment
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In the figure
Angle C(major arc) = 360° - b°
(as Complete angle is 360°)
So In Quadrilateral ABCD
/_ A + /_B + /_C + /_D = 360°
a° + b° + 360° - b° + /_D = 360°
/_D = b° - c° - a°
Therefore
Angle ADC IS = b° - a° - c°
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