Question

in the figure angle QPR equal to angle PQR and M and N are respectively find turn side QR and PR of triangle PQR such that QM equal to PN , prove that OP equal to OQ, where O is the point of intersection of PM and QN​

Answer 1

Answer:

∠QPR = ∠PQR and M and N are respectively points on side QR and PR of ∆PQR, such that QM = PN. To Prove: OP = OQ, where O is the point of intersection of PM and QN. (iii) ∠ABD = ∠BAC. Given: ABCD is a quadrilateral in which AD = BC and ∠DAB = ∠CBA.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Prove that OP = OQ, where O is the point of intersecting of PM and QN. Given: ∠QPR = ∠PQR and M and N are respectively points on side QR and PR of ∆PQR, such that QM = PN. To Prove: OP = OQ, where O is the point of intersection of PM and QN. In quadrilateral ACBD, AC = AD and AB bisects ∠A

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