In the figure angle qrs= angle psr and angle prq= angle psq. prove that qr=ps
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Answer:
Given that:
QP=8cm,PR=6cm and SR=3cm
(I) In △PQR and △SPR
∠PRQ=∠SRP (Common angle)
∠QPR=∠PSR (Given that)
∠PQR=∠PSR (Properties of triangle )
∴△PQR∼△SPR (By AAA)
(II) SPPQ=PRQR=SRPR (Properties of similar triangles)
⇒SP8cm=3cm6cm
⇒SP=4cm and
⇒6cmQR=3cm6cm
⇒QR=12cm
(III)ar(△SPR)ar(△PQR)=SP2PQ2=4282=4
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