In the figure angle X=72° , angle XYZ=46° . If YO and ZO are bisectors of angle xyz and angle xzy respectively of triangle XYZ , find angle OYZ and angle YOZ.
class:- 9th
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Step-by-step explanation:
In the figure angle X=72° , angle XYZ=46° . If YO and ZO are bisectors of angle xyz and angle xzy respectively of triangle XYZ , find angle OYZ and angle YOZ
Step-by-step explanation:
In fig YO and ZO are respectively the bisector , and bisector bisect the angle in two equal parts so
angle (OYZ) = 1/2 angle (XYZ)
angle (OYZ) = 1/2 (46) = 23 DEGREE
NOW IN TRIANGLE XYZ by angle sum property
x+y+z =180
72 +46 +z =180
z = 180 -118
z = 62 degree
- now apply angle sum property in triangle OYZ
angle (OYZ) + angle (OZY)+ angle (YOZ)= 180
angle (OYZ) + angle (OZY)+ angle (YOZ)= 180
23 +31 + angle (YOZ)= 180
ANGLE (YOZ)= 180-54
=126 DEGREE
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