in the figure angle x is equal to 62 degree and Angle xyz is equal to 54 degree if YO and ZO are bisectors of angle xyz and angle xyz respectively of XYZ find angle OZY and angle YOZ.
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we knows that whole angle of triangle is 180 degree = 131+27+z=180degree
z = 180-158=32degree Ans
z = 180-158=32degree Ans
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Given :- angle X = 62° , angle XYZ = 54°
To find :- angle OZY and angle YOZ
angle 1 = 1/2 × 54
angle 1 = 27°
62° + 54° + angle 4 = 180° (angle sum property).
116° + angle 4 = 180°
angle 4 = 180° - 116°
angle 4 = 64°
angle 3 = 1/2 × 64
angle 3 = 32°
angle 1 + angle 2 + angle 3 = 180
° (angle sum property).
27° + angle 2 + 32° = 180°
59° + angle 2 = 180°
angle 2 = 180° - 59°
angle 2 = 121°
Therefore, angle OZY = 32° , angle YOZ = 121°
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