Math, asked by Faisalmuhammed8655, 1 month ago

In the Figure AngleBAD=3 DBA find Angle DBC and Angle ABC

Answers

Answered by harshparikh7a
0

Answer:

CDB= 76° DBC=39° ABC=39°

Step-by-step explanation:

Angle CDB + angleBDA =180°

angle CDB =180°-104°=76°

angle BCD +angleDBC = angleBDA

65° + angleDBC =104°

angle DBC=104°-65°

angle DBC=39°

angle A + angle B+ angle C=180°

3 angle DBA + angle DBC + angle DBA +65°=180°

4 angle DBA + 39°+65°=180

angle DBA =180-104/4=76/4=19°

Similar questions