In the Figure AngleBAD=3 DBA find Angle DBC and Angle ABC
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Answer:
CDB= 76° DBC=39° ABC=39°
Step-by-step explanation:
Angle CDB + angleBDA =180°
angle CDB =180°-104°=76°
angle BCD +angleDBC = angleBDA
65° + angleDBC =104°
angle DBC=104°-65°
angle DBC=39°
angle A + angle B+ angle C=180°
3 angle DBA + angle DBC + angle DBA +65°=180°
4 angle DBA + 39°+65°=180
angle DBA =180-104/4=76/4=19°
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