Question

in the figure aob and cod are straight lines. if aoe = 90 and bod = 48. find the aoc and doe
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Answer 1

Answer:

(i) ∠AOB + ∠BOC = 180°

> 50° + ∠BOC = 180°

> ∠BOC = 180° - 50° = 130°

> ∠BOC = 130°

(ii) ∠EOD + ∠COD = 90°

> ∠EOD + 25° = 90°

> ∠EOD + 25° = 90°

> ∠EOD = 90° - 25°

> ∠EOD = 65°

(iii) ∠BOD = ∠BOC + ∠COD

= 130° + 25° = 205°

(iv) ∠BOD = 360° - ∠BOD

= 360° - 155° = 205°

(v) ∠COE = 360° - ∠COE

= 360° (∠COD + ∠EOD)

= 360° - (25° + 65°)

= 360° - 90° = 270°