Math, asked by ranawaseem1974, 2 months ago


In the figure AOB and COD are straight lines. If AOE = 90° and DOE = 53°
Find
a. AOC
b. BOD

Answers

Answered by mausumi19
2

Answer:

Since AOB is a straight line, we have

∠AOE+∠BOE=180

o

=3x

o

+72

o

=180

o

⇒3x

o

=108

o

⇒x=36

o

We also know that

∴∠AOC+∠COD+∠BOD=180

o

(∵ straight angle)

⇒x

o

+90

o

+y

o

=180

o

⇒36

o

+90

o

+y

o

=180

o

y

o

=180

o

−126

o

=54

o

∴∠AOC=36

o

,∠BOD=54

o

and ∠AOE=108

o

Answered by ayeshahaseeb72
1

a. AOC

= 48⁰ (vertically opposite)

b. DOE

= 42⁰

The answer of b part is 42⁰ because angle AOE, BOD and DOE all form on a straight line. A straight line is always of 180⁰. So add angle AOE= 90 and BOD= 48. The sum of them would be 138⁰. Minus 138 FROM 180⁰. Your answer would be 42⁰.

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