In the figure AOB and COD are straight lines. If AOE = 90° and DOE = 53°
Find
a. AOC
b. BOD
Answers
Answered by
2
Answer:
Since AOB is a straight line, we have
∠AOE+∠BOE=180
o
=3x
o
+72
o
=180
o
⇒3x
o
=108
o
⇒x=36
o
We also know that
∴∠AOC+∠COD+∠BOD=180
o
(∵ straight angle)
⇒x
o
+90
o
+y
o
=180
o
⇒36
o
+90
o
+y
o
=180
o
y
o
=180
o
−126
o
=54
o
∴∠AOC=36
o
,∠BOD=54
o
and ∠AOE=108
o
Answered by
1
a. AOC
= 48⁰ (vertically opposite)
b. DOE
= 42⁰
The answer of b part is 42⁰ because angle AOE, BOD and DOE all form on a straight line. A straight line is always of 180⁰. So add angle AOE= 90 and BOD= 48. The sum of them would be 138⁰. Minus 138 FROM 180⁰. Your answer would be 42⁰.
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